A. Decimal=160, hexadecimal=00
B. Decimal=170, hexadecimal=AA
C. Decimal=180, hexadecimal=BB
D. Decimal=190, hexadecimal=CC
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A./38
B./30
C./27
D./23
E./18
F./32
A. 255.255.255.0
B. 255.255.255.240
C. 255.255.255.248
D. 255.255.255.252
E. 255.255.255.254
A. Deleting unusable addresses through the creation of many subnets.
B. Combining routes to multiple networks into one supernet.
C. Reclaiming unused space by means of changing the subnet size.
D. Calculating the available host addresses in the AS.
A. Static NAT
B. Port loading
C. NAT Overloading
D. Dynamic NAT
E. None of the above
A.172.16.42.0
B.172.16.107.0
C.172.16.208.0
D.172.16.252.0
E.172.16.254.0
最新試題
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