A.vertically above the center of buoyancy
B.vertically above the center of gravity
C.at the intersection of the upright vertical centerline and the line of action of the buoyant force
D.at the geometric center of the underwater volume
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A.The foot/tons needed to trim the vessel by 1 inch
B.The foot/tons needed to trim the vessel by 1 foot
C.The moments needed to trim the vessel by 1 centimeter
D.The amount of vessel will trim when loading 100 tons 100 feet from the tipping Center
A.The metacenter does not remain in the same position for large angles of inclination
B.The center of gravity shifts due to inclination
C.The center of gravity shifts above the metacenter as the vessel is inclined
D.The mean draft will change as the vessel is inclined
A.list
B.heel
C.trim
D.flotation
A.KG is increased
B.KG is decreased
C.KG is not affected
D.KG increases at light drafts and decreases at deep drafts
A.only when there is positive stability
B.only when there is negative stability
C.only when there is neutral stability
D.at all times
最新試題
For small angles of inclination,if the KG were equal to the KM,then the vessel would have().
A vessel trimmed by the stern has a().
A vessel’s KG is determined by().
A ship lists and trims about the().
A vessel with a large GM will().
A floating vessel will behave as if all of its weight is acting downward through the().
A wind has caused a difference between drafts starboard and port. This difference is().
Semisubmersibles A and B are identical. However,A is more tender than B. This means that A relative to B has a().
For a ship with longitudinal inclination,an increase in GML causes().
An upright vessel has negative GM. GM becomes positive at the angle of loll because the().